4^x-5=16^2x-31

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Solution for 4^x-5=16^2x-31 equation: 



4^x-5=16^2x-31

We move all terms to the left:

4^x-5-(16^2x-31)=0

We get rid of parentheses

4^x-16^2x+31-5=0

We add all the numbers together, and all the variables

4^x-16^2x+26=0

We move all terms containing x to the left, all other terms to the right

4^x-16^2x=-26

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